.bashrc에서 에코 할 때 SCP가 작동하지 않습니까?
Fedora에 두 명의 사용자가 있습니다.
- 와니
- 뿌리 (아주 분명!)
사용자 Wani의 .bashrc 내용은 다음과 같습니다.
# .bashrc
echo "Hello"
# Source global definitions
if [ -f /etc/bashrc ]; then
. /etc/bashrc
fi
# User specific aliases and functions
이제 루트에 로그인 한 후 다음 명령을 입력합니다.
[root@Dell Wani]# touch try.txt
[root@Dell Wani]# service sshd start
[root@Dell Wani]# scp try.txt Wani@localhost:~/
Wani@localhost's password:
Hello
[root@Dell Wani]#
이제 Wani에 로그인하고 다음을 입력합니다.
[Wani@Dell ~]$ cat try.txt
cat: try.txt: No such file or directory
[Wani@Dell ~]$
이제 다시 루트에 로그인하고 다음과 같은 명령을 입력합니다 -v
.
[root@Dell Wani]# scp -v morph.log Wani@localhost:
Executing: program /usr/bin/ssh host localhost, user Wani, command scp -v -t -- .
OpenSSH_5.6p1, OpenSSL 1.0.0j-fips 10 May 2012
debug1: Reading configuration data /etc/ssh/ssh_config
debug1: Applying options for *
debug1: Connecting to localhost [127.0.0.1] port 22.
debug1: Connection established.
debug1: permanently_set_uid: 0/0
debug1: identity file /root/.ssh/id_rsa type -1
debug1: identity file /root/.ssh/id_rsa-cert type -1
debug1: identity file /root/.ssh/id_dsa type -1
debug1: identity file /root/.ssh/id_dsa-cert type -1
debug1: Remote protocol version 2.0, remote software version OpenSSH_5.6
debug1: match: OpenSSH_5.6 pat OpenSSH*
debug1: Enabling compatibility mode for protocol 2.0
debug1: Local version string SSH-2.0-OpenSSH_5.6
debug1: SSH2_MSG_KEXINIT sent
debug1: SSH2_MSG_KEXINIT received
debug1: kex: server->client aes128-ctr hmac-md5 none
debug1: kex: client->server aes128-ctr hmac-md5 none
debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent
debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP
debug1: SSH2_MSG_KEX_DH_GEX_INIT sent
debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY
debug1: Host 'localhost' is known and matches the RSA host key.
debug1: Found key in /root/.ssh/known_hosts:2
debug1: ssh_rsa_verify: signature correct
debug1: SSH2_MSG_NEWKEYS sent
debug1: expecting SSH2_MSG_NEWKEYS
debug1: SSH2_MSG_NEWKEYS received
debug1: Roaming not allowed by server
debug1: SSH2_MSG_SERVICE_REQUEST sent
debug1: SSH2_MSG_SERVICE_ACCEPT received
debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi- with-mic,password
debug1: Next authentication method: gssapi-keyex
debug1: No valid Key exchange context
debug1: Next authentication method: gssapi-with-mic
debug1: Unspecified GSS failure. Minor code may provide more information
Credentials cache file '/tmp/krb5cc_0' not found
debug1: Unspecified GSS failure. Minor code may provide more information
Credentials cache file '/tmp/krb5cc_0' not found
debug1: Unspecified GSS failure. Minor code may provide more information
debug1: Unspecified GSS failure. Minor code may provide more information
debug1: Next authentication method: publickey
debug1: Trying private key: /root/.ssh/id_rsa
debug1: Trying private key: /root/.ssh/id_dsa
debug1: Next authentication method: password
Wani@localhost's password:
debug1: Authentication succeeded (password).
Authenticated to localhost ([127.0.0.1]:22).
debug1: channel 0: new [client-session]
debug1: Requesting no-more-sessions@openssh.com
debug1: Entering interactive session.
debug1: Sending environment.
debug1: Sending env XMODIFIERS = @im=none
debug1: Sending env LANG = en_US.UTF-8
debug1: Sending command: scp -v -t -- .
Hello
[root@Dell Wani]# debug1: client_input_channel_req: channel 0 rtype exit-status reply 0
debug1: channel 0: free: client-session, nchannels 1
debug1: fd 0 clearing O_NONBLOCK
debug1: fd 1 clearing O_NONBLOCK
Transferred: sent 1664, received 1976 bytes, in 0.1 seconds
Bytes per second: sent 22961.5, received 27266.8
debug1: Exit status 0
(그리고 Enter 키를 누른 후)
[root@Dell Wani]#
누구든지 여기서 정확히 무슨 일이 일어 났는지 밝힐 수 있습니까? 왜 파일이 루트에서 Wani로 복사되지 않았습니까?
echo
in a .bashrc
를 사용 하면 stdin / stdout 채널을 통해 프로토콜 데이터를 볼 수 있으므로 중단 scp
됩니다 scp
. 이 문제에 대한 자세한 내용은 https://bugzilla.redhat.com/show_bug.cgi?id=20527 을 참조 하십시오 .
사용 가능한 몇 가지 해결 방법이 있습니다.
- '대화 형'플래그의 조건 (예 :
case $- in *i*
tripleee에서 제안한대로) - Use the
tty
utility to detect an interactive shell (e.g.if tty > /dev/null
orif [ -t 0 ]
) - Check the value of
$SSH_TTY
I suppose you should use whichever one works for you. I don't know what the best (most portable/most reliable) option is, unfortunately.
To add to nneonneo's options, you can also condition with the interactive flag with
if [[ $- =~ "i" ]]
which I think is possibly the clearest way in bash.
This works for me,
In .bashrc
add first line as:
if [ -z "$PS1" ]; then
return
fi
https://superuser.com/questions/690735/can-i-tell-if-im-in-an-scp-session-in-my-bashrc
The default Ubuntu .bashrc
contains the following snippet which already takes care of the problem:
# If not running interactively, don't do anything
case $- in
*i*) ;;
*) return;;
esac
In .bashrc
, use STDERR as output instead:
echo "# Important Notice" >&2
Update: do not use it! We had an issue recently that a (closed source) tool failed due to an echo
to STDERR in .bashrc
. The tool (using rcp
) expected no output at all, neither on STDOUT nor STDERR. And it stuck when it got the echo. Lesson learned: make separate accounts for humans and for machines (scripts), or just stop tattling via .bashrc
.
The most portable way of testing for an interactive shell seems to be:
test -t 0
if [ $? -eq 0 ]
then
# interactive
;
else
# non-interactive
;
fi
nneonneo's solution worked for me as well. But since my default shell is TCSH, I had to slightly edit the fix as follows (in .tcshrc):
if ( $?SSH_TTY ) then
exec /bin/bash
endif
Just thought I would share for everyone's benefit.
if [ 0 -eq $(shopt -q login_shell; echo $?) ]; then
echo "do something?"
fi
If you're on Red Hat Enterprise Linux (RHEL) or variant, drop a script that does the echo
, or whatever you want, into /etc/profile.d/
If you want echo statements as well, the from @Blauhirn's answer, you can keep placing your echo statement/s after the case condition.
case $- in
*i*) ;;
*) return;;
esac
echo "Your Greeting/Warning Message/s here!"
참고URL : https://stackoverflow.com/questions/12440287/scp-doesnt-work-when-echo-in-bashrc
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