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JSONarray를 ArrayList로 변환
JSON 문자열을 다운로드하고 JSONArray로 변환하고 있습니다. 나는 그것을 목록보기에 넣고 나중에 그 목록보기에서 삭제할 수 있어야하며 JSONArray에는 .remove 메서드가 없기 때문에 (Obama에게 감사드립니다) 배열 목록으로 변환하려고합니다.
여기 내 JSON (array.toString ())이 있습니다.
[{"thumb_url":"tb-1370913834.jpg","event_id":"15","count":"44","event_tagline":"this is a tagline","event_name":"5th birthday","event_end":"1370919600","event_start":"1370876400"}]
배열로 가져 와서 각각의 키로 문자열을 호출 할 수 있어야합니다. 도움을 주셔서 감사합니다!
ArrayList<String> listdata = new ArrayList<String>();
JSONArray jArray = (JSONArray)jsonObject;
if (jArray != null) {
for (int i=0;i<jArray.length();i++){
listdata.add(jArray.getString(i));
}
}
나는 Gson(Google에서) 사용하여 해냈습니다 .
모듈에 다음 행을 추가하십시오 build.gradle.
dependencies {
// ...
// Note that `compile` will be deprecated. Use `implementation` instead.
// See https://stackoverflow.com/a/44409111 for more info
implementation 'com.google.code.gson:gson:2.8.2'
}
JSON 끈:
private String jsonString = "[\n" +
" {\n" +
" \"id\": \"c200\",\n" +
" \"name\": \"Ravi Tamada\",\n" +
" \"email\": \"ravi@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c201\",\n" +
" \"name\": \"Johnny Depp\",\n" +
" \"email\": \"johnny_depp@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c202\",\n" +
" \"name\": \"Leonardo Dicaprio\",\n" +
" \"email\": \"leonardo_dicaprio@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c203\",\n" +
" \"name\": \"John Wayne\",\n" +
" \"email\": \"john_wayne@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c204\",\n" +
" \"name\": \"Angelina Jolie\",\n" +
" \"email\": \"angelina_jolie@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c205\",\n" +
" \"name\": \"Dido\",\n" +
" \"email\": \"dido@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c206\",\n" +
" \"name\": \"Adele\",\n" +
" \"email\": \"adele@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c207\",\n" +
" \"name\": \"Hugh Jackman\",\n" +
" \"email\": \"hugh_jackman@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c208\",\n" +
" \"name\": \"Will Smith\",\n" +
" \"email\": \"will_smith@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c209\",\n" +
" \"name\": \"Clint Eastwood\",\n" +
" \"email\": \"clint_eastwood@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c2010\",\n" +
" \"name\": \"Barack Obama\",\n" +
" \"email\": \"barack_obama@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c2011\",\n" +
" \"name\": \"Kate Winslet\",\n" +
" \"email\": \"kate_winslet@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c2012\",\n" +
" \"name\": \"Eminem\",\n" +
" \"email\": \"eminem@gmail.com\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" }\n" +
" ]";
ContactModel.java:
public class ContactModel {
public String id;
public String name;
public String email;
}
JSON 문자열을 ArrayList<Model>다음으로 변환하는 코드 :
참고 : 다음을 가져와야합니다 java.lang.reflect.Type;.
// Top of file
import java.lang.reflect.Type;
// ...
private void parseJSON() {
Gson gson = new Gson();
Type type = new TypeToken<List<ContactModel>>(){}.getType();
List<ContactModel> contactList = gson.fromJson(jsonString, type);
for (ContactModel contact : contactList){
Log.i("Contact Details", contact.id + "-" + contact.name + "-" + contact.email);
}
}
이것이 당신을 도울 것입니다.
try this way Simply loop through that, building your own array. This code assumes it's an array of strings, it shouldn't be hard to modify to suit your particular array structure.
JSONArray jsonArray = new JSONArray(jsonArrayString);
List<String> list = new ArrayList<String>();
for (int i=0; i<jsonArray.length(); i++) {
list.add( jsonArray.getString(i) );
Instead of converting the JSON string to an ArrayList or even a Map, you can just create a JSONObject itself. This object has the ability to get string values by key, as you want and also to remove objects.
To create a JSONObject from a properly formatted JSON string, you simply call the appropriate constructor.
JSONObject json = new JSONObject(jsonString);
I have fast solution. Just create a file ArrayUtil.java
import java.util.ArrayList;
import java.util.Collection;
import org.json.JSONArray;
import org.json.JSONException;
public class ArrayUtil
{
public static ArrayList<Object> convert(JSONArray jArr)
{
ArrayList<Object> list = new ArrayList<Object>();
try {
for (int i=0, l=jArr.length(); i<l; i++){
list.add(jArr.get(i));
}
} catch (JSONException e) {}
return list;
}
public static JSONArray convert(Collection<Object> list)
{
return new JSONArray(list);
}
}
Usage:
ArrayList<Object> list = ArrayUtil.convert(jArray);
or
JSONArray jArr = ArrayUtil.convert(list);
JSONArray array = new JSONArray(json);
List<JSONObject> list = new ArrayList();
for (int i = 0; i < array.length();list.add(array.getJSONObject(i++)));
In Java 8,
IntStream.range(0,jsonArray.length()).mapToObj(i->jsonArray.getString(i)).collect(Collectors.toList())
To make it handy, use POJO.
try like this..
List<YourPojoObject> yourPojos = new ArrayList<YourPojoObject>();
JSONObject jsonObject = new JSONObject(jsonString);
YourPojoObject yourPojo = new YourPojoObject();
yourPojo.setId(jsonObject.getString("idName"));
...
...
yourPojos.add(yourPojo);
I have fast solution. Just create a file ArrayUtil.java
ObjectMapper mapper = new ObjectMapper();
List<Student> list = Arrays.asList(mapper.readValue(jsonString, Student[].class));
Usage:
ArrayList<Object> list = ArrayUtil.convert(jArray);
or
JSONArray jArr = ArrayUtil.convert(list);
public static List<JSONObject> getJSONObjectListFromJSONArray(JSONArray array)
throws JSONException {
ArrayList<JSONObject> jsonObjects = new ArrayList<>();
for (int i = 0;
i < (array != null ? array.length() : 0);
jsonObjects.add(array.getJSONObject(i++))
);
return jsonObjects;
}
Generic variant
private interface ParseCallable<T> {
T call(JSONArray jsonArray, int index) throws JSONException;
}
private <T> List<T> getList(JSONArray jsonArray, ParseCallable<T> callable) throws Exception {
List<T> list = new ArrayList<>(jsonArray.length());
for (int i = 0; i < jsonArray.length(); i++) {
T t = callable.call(jsonArray, i);
list.add(t);
}
return list;
}
Usage
List<String> listKeyString = getList(dataJsonObject.getJSONArray("keyString"), new ParseCallable<String>() {
@Override
public String call(JSONArray jsonArray, int index) throws JSONException {
return jsonArray.getString(index);
}
});
List<Integer> listKeyInteger = getList(dataJsonObject.getJSONArray("keyInteger"), new ParseCallable<Integer>() {
@Override
public Integer call(JSONArray jsonArray, int index) throws JSONException {
return jsonArray.getInt(index);
}
});
참고URL : https://stackoverflow.com/questions/17037340/converting-jsonarray-to-arraylist
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